A random sample of 17 values from a normal population has a mean of 105 cm and the sample standard deviation is 8.489. If normal population mean is 110 cm, then the upper limit of confidence at 5% level of significance is : (Given $t_{16}(0.05) = 2.12$)

Rajesh calculated 95% confidence level. What does he mean by that?

(A) He can be 95% confident that his sample will include the population parameter.

(B) He can be 95% confused that his sample will include the population parameter.

(C) He can be 5% confident that his sample will not include the population parameter.

(D) He can be 5% confident that his sample will include the population parameter.

Choose the correct answer from the options given below:

In reference to Inferential Statistics, for 20 degrees of freedom, the least statistical t-value among the given below is:

A random sample consists of five observations: 2,4,5,6,8. The point estimate of the population mean is :

If X is normally distributed with mean 30 and standard deviation 5, the value of $P(26 \le X \le 34)$ is: (Where $P(0 \le Z \le 0.8) = 0.2881$)

The following data are from a simple random sample: 3, 6, 8, 15, 5, 11. What is the point estimate of the population mean?

A 95 % confidence interval states that the population mean is greater than 152 and less than 160. If $\sigma = 15$ and $Z_{0.025} = 1.96$, then what sample size was used in the study?