Skip to main contentSkip to solution

Match List-I with List-II

List-I (Singular matrix)List-II (A value of xx)
(A) A=[x422x]A=\begin{bmatrix}x & 4 \\ 2 & 2x\end{bmatrix}(I) 3
(B) A=[3x3x9]A=\begin{bmatrix}3 & x \\ 3x & 9\end{bmatrix}(II) 4
(C) A=[x11x]A=\begin{bmatrix}x & 1 \\ 1 & x\end{bmatrix}(III) 2
(D) A=[x116x]A=\begin{bmatrix}x & 1 \\ 16 & x\end{bmatrix}(IV) 1

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 1

A matrix is singular when its determinant is zero.

(A) 2x2−8=0⇒x=±22x^2-8 = 0 \Rightarrow x = \pm2, so x=2x=2.

(B) 27−3x2=0⇒x=±327-3x^2 = 0 \Rightarrow x = \pm3, so x=3x=3.

(C) x2−1=0⇒x=±1x^2-1 = 0 \Rightarrow x = \pm1, so x=1x=1.

(D) x2−16=0⇒x=±4x^2-16 = 0 \Rightarrow x = \pm4, so x=4x=4.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question