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Solution

✅ Correct Option: 3

Only the units digit of the base matters, so consider 2132^{13}.

The units digits of powers of 2 cycle as 2,4,8,62, 4, 8, 6 with period 4.

Since 13≡1(mod4)13 \equiv 1 \pmod 4, the last digit is the first in the cycle, namely 22.

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