(x-3)e^x/(x-1)^3dx is equal to: (where C is an arbitrary constant) Option 1: 1/e^x(x-1)^2+C Option 2: (x-1)^2/e^x+C Option 3: (x-1)^2e^x+C Option 4: e^x/(x-1)^2+C

The answer is 'e^x/(x-1)^2+C'. View full solution:

CUET Mathematics - (x-3)e^x/(x-1)^3dx is equal to: (where C is an arbitrary constant) | PYQs + Solutions

CUET Mathematics 2026 29th May Shift 1

Calculus

Medium

core

$\dfrac{1}{e^x(x-1)^2}+C$

$\dfrac{(x-1)^2}{e^x}+C$

$(x-1)^2e^x+C$

$\dfrac{e^x}{(x-1)^2}+C$

✅ Correct Option: 4

Related questions:

18th May Shift 1

Match List-I with List-II

List-I	List-II
(A) $\displaystyle\int_{\pi/6}^{\pi/3} \cos x \, dx$	(I) $0$
(B) $\displaystyle\int_{-\pi}^{\pi} (\sin^{61}x + x^{123}) \, dx$	(II) $4$
(C) $\displaystyle\int_{0}^{\pi/2} \dfrac{1}{1+\tan^3 x} \, dx$	(III) $\dfrac{\sqrt{3}-1}{2}$
(D) $\displaystyle\int_{-2}^{2} (2 - \left\vert x \right\vert) \, dx$	(IV) $\dfrac{\pi}{4}$

Choose the correct answer from the options given below:

26th May Shift 2

The value of $\displaystyle\int_0^1 xe^{x^2}\,dx$ is equal to :

29th May Shift 2

If $\int \frac{\sin^6 x}{\cos^{10} x}\,dx = -2a\tan^9 x + b\tan^7 x + c$ , (where c is an arbitrary constant), then which one of the following is TRUE?

CUET Mathematics 2026 29th May Shift 1 PYQs

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