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Which of the following are correct?

(A) If A=[7543]A=\begin{bmatrix}7 & 5 \\ 4 & 3\end{bmatrix}, then A−1=[3−5−47]A^{-1}=\begin{bmatrix}3 & -5 \\ -4 & 7\end{bmatrix}

(B) If A=[35610]A=\begin{bmatrix}3 & 5 \\ 6 & 10\end{bmatrix}, then AA is a non-singular matrix

(C) A=[0−553]A=\begin{bmatrix}0 & -5 \\ 5 & 3\end{bmatrix} is a symmetric matrix

(D) If A=[6xy0]A=\begin{bmatrix}6 & x \\ y & 0\end{bmatrix} and A=ATA=A^T, then x=yx=y

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 3

(A) ∣A∣=21−20=1|A| = 21-20 = 1, so A−1=adjA=[3−5−47]A^{-1} = adj A = \begin{bmatrix}3&-5\\-4&7\end{bmatrix}: correct.

(B) ∣A∣=30−30=0|A| = 30-30 = 0, so the matrix is singular: incorrect.

(C) Here a12=−5≠a21=5a_{12} = -5 \neq a_{21} = 5, so it is not symmetric: incorrect.

(D) A=ATA = A^T forces x=yx = y: correct.

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