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The general solution of the differential equation dydx=2−y\dfrac{dy}{dx}=2^{-y} is:

(where cc is an arbitrary constant)

Solution

✅ Correct Option: 3

Separating gives 2ydy=dx2^y dy = dx.

Since ∫2ydy=2ylog⁡e2\int 2^y dy = \dfrac{2^y}{\log_e 2}, we get 2ylog⁡e2=x+k\dfrac{2^y}{\log_e 2} = x + k.

Multiplying by log⁡e2\log_e 2: 2y=xlog⁡e2+c2^y = x\log_e 2 + c.

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