The general solution of the differential equation dy/dx=2^-y is: (where c is an arbitrary constant) Option 1: 2^y=x^2_e2+c Option 2: 2^y=x_e2+cx Option 3: 2^y=x_e2+c Option 4: 2^y=-x_e2+c

The answer is '2^y=x_e2+c'. View full solution:

CUET Mathematics - The general solution of the differential equation dy/dx=2^-y is: (where c is an arbitrary constant) | PYQs + Solutions

CUET Mathematics 2026 29th May Shift 1

Calculus

Easy

common

$2^y=x^2\log_e2+c$

$2^y=x\log_e2+cx$

$2^y=x\log_e2+c$

$2^y=-x\log_e2+c$

✅ Correct Option: 3

Related questions:

15 May Shift 1

For $|x| < 1$ , if $x = \cos\left(\frac{1}{a}\log y\right)$ , then

29th May Shift 2

In reference to the differential equation : $y''+y=(e)^{y'}$ , which of the following statements are correct ?

A. The order of the differential equation is 1.

B. The degree of the differential equation is 1.

C. The order of the differential equation is 2.

D. The degree of the differential equation is not defined.

Choose the correct answer from the options given below:

13 May Shift 2

Match List-I with List-II

List-I	List-II
Differential equation	Degree
(A) $\frac{d^2y}{dx^2} + \sqrt{\frac{dy}{dx}} - y = 0$	(I) 6
(B) $\sqrt{\frac{d^3y}{dx^3}} - \sqrt[12]{\frac{d^2y}{dx^2}} = 0$	(II) Not defined
(C) $\left(\frac{d^2y}{dx^2}\right)^2 + \frac{dy}{dx} + e^{\frac{dx}{dx}} = x^2$	(III) 3
(D) $\sqrt[3]{\frac{dy}{dx}} - \frac{d^2y}{dx^2} = e^x$	(IV) 2

Choose the correct answer from the options given below: