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If A=[xpx+pyqy+qzrz+r]A=\begin{bmatrix} x & p & x+p \\ y & q & y+q \\ z & r & z+r \end{bmatrix}, then ∣A∣|A| is

Solution

✅ Correct Option: 3

The third column is exactly the sum of the first two columns, i.e. C3=C1+C2C_3 = C_1 + C_2.

Applying C3→C3−C1−C2C_3 \to C_3 - C_1 - C_2 makes the third column all zeros, so the determinant is 00.

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