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If A=[3−2321−14−32]A=\begin{bmatrix}3 & -2 & 3 \\ 2 & 1 & -1 \\ 4 & -3 & 2\end{bmatrix} and A(adjA)=xIA(adjA)=xI, where II is an identify matrix of order 3, then xx is equal to

Solution

✅ Correct Option: 1

The identity A(adjA)=∣A∣IA(adj A) = |A|I means x=∣A∣x = |A|.

Expanding along the first row:

∣A∣=3(2−3)+2(4+4)+3(−6−4)=−3+16−30=−17|A| = 3(2-3) + 2(4+4) + 3(-6-4) = -3 + 16 - 30 = -17.

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