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Bag A contains 3 red and 5 white balls and bag B contains 4 red and 4 white balls. A bag is selected at random, and a ball is drawn. Then the probability of getting a red ball is:

Solution

✅ Correct Option: 2

Each bag is equally likely, so by total probability:

P(red)=12×38+12×48=316+416=716P(\text{red}) = \dfrac{1}{2}\times\dfrac{3}{8} + \dfrac{1}{2}\times\dfrac{4}{8} = \dfrac{3}{16}+\dfrac{4}{16} = \dfrac{7}{16}.

This equals 0.43750.4375, which lies between 0.330.33 and 0.500.50.

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