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If AB→=2i^+3j^−k^\overrightarrow{AB}=2\hat i+3\hat j-\hat k and AC→=3i^−2j^+4k^\overrightarrow{AC}=3\hat i-2\hat j+4\hat k are the two sides of a triangle ABC, then the length of the median through vertex A is equal to

Solution

✅ Correct Option: 3

If MM is the midpoint of BCBC, then AM→=AB→+AC→2=5i^+j^+3k^2\overrightarrow{AM} = \dfrac{\overrightarrow{AB}+\overrightarrow{AC}}{2} = \dfrac{5\hat i+\hat j+3\hat k}{2}.

So the median length is 25+1+92=352\dfrac{\sqrt{25+1+9}}{2} = \dfrac{\sqrt{35}}{2} units.

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