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If the function f(x)={3x−6,x≤54k,x>5f(x)=\begin{cases}3x-6, & x \le 5 \\ 4k, & x>5\end{cases} is continuous at x=5x=5, then the value of kk is:

Solution

✅ Correct Option: 4

Continuity at x=5x=5 requires the left limit to equal the right limit.

Left limit and value: 3(5)−6=93(5)-6 = 9. Right limit: 4k4k.

So 4k=94k = 9, giving k=94k = \dfrac{9}{4}.

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