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Ram wishes to purchase a house for ₹ 15,00,000 and made a down payment of ₹ 5,00,000. If he can amortize the balance at 9% per annum compounded monthly for 25 years, then his EMI is:

[Given (1.0075)300≈9.41(1.0075)^{300} ≈ 9.41]

Solution

✅ Correct Option: 4
  • Principal Loan Amount (PP): ₹ 15,00,000−₹ 5,00,000=₹ 10,00,00015,00,000 - \text{₹ } 5,00,000 = \text{₹ } 10,00,000
  • Monthly Interest Rate (ii): 9%12=0.75%=0.0075\frac{9\%}{12} = 0.75\% = 0.0075
  • Total Months (nn): 25×12=30025 \times 12 = 300

Using the EMI formula:

EMI=P×i×(1+i)n(1+i)n−1\text{EMI} = \frac{P \times i \times (1+i)^n}{(1+i)^n - 1}

Substitute the given value (1.0075)300≈9.41(1.0075)^{300} \approx 9.41:

EMI=10,00,000×0.0075×9.419.41−1\text{EMI} = \frac{10,00,000 \times 0.0075 \times 9.41}{9.41 - 1}

EMI=70,5758.41≈₹ 8,391.80\text{EMI} = \frac{70,575}{8.41} \approx \mathbf{\text{₹ } 8,391.80}

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