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If the matrix A=[a3bc0−1−210]A = \begin{bmatrix}a & 3 & b\\ c & 0 & -1\\ -2 & 1 & 0\end{bmatrix} is skew-symmetric, then 4a+3b+2c4a+3b+2c is equal to

Solution

✅ Correct Option: 3

A skew-symmetric matrix has zero diagonal and aij=−ajia_{ij} = -a_{ji}.

So a=0a = 0; from a13=−a31a_{13} = -a_{31}, b=2b = 2; from a21=−a12a_{21} = -a_{12}, c=−3c = -3.

Hence 4a+3b+2c=0+6−6=04a+3b+2c = 0+6-6 = 0.

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