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Rakshita plans to buy a house for Rs.1,00,00,000 with down payment of 20% of the value of house paid by her mother, Rest of the amount she wishes to pay in 25 years by equal monthly installment at an interest of 9% per annum compounded monthly. Then the EMI paid by her is: (Given (1.0075)300(1.0075)^{300} = 9 )

Solution

Correct Option: 4

House Price: Rs. 1,00,00,000

Down Payment (paid by mother): 20% of house price

Down Payment =20100×1,00,00,000= \dfrac{20}{100} \times 1,00,00,000

Down Payment =Rs. 20,00,000= \text{Rs. } 20,00,000

Loan Amount =House PriceDown Payment= \text{House Price} - \text{Down Payment}

Loan Amount =1,00,00,00020,00,000= 1,00,00,000 - 20,00,000

Loan Amount =Rs. 80,00,000= \text{Rs. } 80,00,000


Annual Interest Rate: 9% per annum

Monthly Interest Rate =9%12=0.75%=0.0075= \dfrac{9\%}{12} = 0.75\% = 0.0075

Time Period =25 years=25×12=300 months= 25 \text{ years} = 25 \times 12 = 300 \text{ months}


The EMI formula is:

EMI=P×r×(1+r)n(1+r)n1\text{EMI} = \dfrac{P \times r \times (1+r)^n}{(1+r)^n - 1}

Where:

P=80,00,000P = 80,00,000 (Principal)

r=0.0075r = 0.0075 (Monthly interest rate)

n=300n = 300 (Number of months)


Substituting the values:

EMI=80,00,000×0.0075×(1.0075)300(1.0075)3001\text{EMI} = \dfrac{80,00,000 \times 0.0075 \times (1.0075)^{300}}{(1.0075)^{300} - 1}

Given (1.0075)300=9(1.0075)^{300} = 9:

EMI=80,00,000×0.0075×991\text{EMI} = \dfrac{80,00,000 \times 0.0075 \times 9}{9 - 1}

EMI=6,00,000×98\text{EMI} = \dfrac{6,00,000 \times 9}{8}

EMI=54,00,0008\text{EMI} = \dfrac{54,00,000}{8}

EMI=Rs. 67,500\text{EMI} = \text{Rs. } 67,500

Therefore, the EMI paid by Rakshita is Rs. 67,500.

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