CUET Mathematics - Let the equation of lines be as L_1: r = a_1 + _1 and L_2: r_2 = a_2 + _2 such that d_1 - d_2 = 2i + 4j + 4k and a_1 x a_2 = 2i - 4j + 4k. Then the shortest distance between L_1 and L_2 is | PYQs + Solutions

CUET Mathematics 2025 29 May Shift 2

Geometry

Medium

core

$2\sqrt{3}$

✅ Correct Option: 3

Related questions:

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The vector equation of line passing through $(-1, 3, -2)$ and perpendicular to the lines $\frac{x+4}{1} = \frac{y}{2} = \frac{z-3}{3}$ and $\frac{x+2}{-3} = \frac{y+5}{2} = \frac{z-6}{5}$ is

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Consider the equation of the line $\vec{r} = -\hat{i} + 2\hat{k} + \mu(4\hat{i} - \hat{j} + 2\hat{k})$ .

Match List-I with List-II

List-I	List-II
(A) It passes through the point	(I) 4, -1, 2
(B) Its direction ratios are	(II) $\frac{4}{\sqrt{21}}, \frac{-1}{\sqrt{21}}, \frac{2}{\sqrt{21}}$
(C) Its Cartesian form is	(III) (-1, 0, 2)
(D) Its direction cosines are	(IV) $\frac{x+1}{4} = \frac{y}{-1} = \frac{z-2}{2}$

Choose the correct answer from the options given below:

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The value of p so that the lines $\frac{x-1}{-3} = \frac{2y-2}{2p} = \frac{z-3}{2}$ and $\frac{x-1}{-3p} = \frac{y-1}{4} = \frac{6-z}{5}$ are at right angles is

CUET Mathematics 2025 29 May Shift 2 PYQs

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