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The system of equation 2x+λy=82x + \lambda y = 8, λx+8y=3\lambda x + 8y = 3

has a unique solution if the value of λ\lambda is (are):

Solution

✅ Correct Option: 1

For the system of equations:

2x+λy=82x + \lambda y = 8

λx+8y=3\lambda x + 8y = 3

The system has a unique solution when the coefficient determinant is non-zero.


The coefficient matrix is:

(2λλ8)\begin{pmatrix} 2 & \lambda \\ \lambda & 8 \end{pmatrix}

The determinant is:

Δ=(2)(8)−(λ)(λ)\Delta = (2)(8) - (\lambda)(\lambda)

Δ=16−λ2\Delta = 16 - \lambda^2


For a unique solution, the determinant must be non-zero:

16−λ2≠016 - \lambda^2 \neq 0

16≠λ216 \neq \lambda^2

λ2≠16\lambda^2 \neq 16

λ≠±4\lambda \neq \pm 4


Therefore, the system has a unique solution for all values of λ\lambda except λ=4\lambda = 4 and λ=−4\lambda = -4.

The answer is: λ≠±4\lambda \neq \pm 4

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