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In a 500 metres race, the ratio of speeds of two participants Meena and Kamal is 4:5 respectively. If Meena has a start of 200 metres, find the distance by which Meena wins.

Solution

Correct Option: 2

The race distance is 500 metres. The speed ratio of Meena to Kamal is 4:5. Meena has a head start of 200 metres.

Since Meena starts 200m ahead, the distance she needs to cover is:

500200=300500 - 200 = 300 metres

Kamal starts from the beginning and needs to cover the full 500 metres.


Let Meena's speed be 4x4x m/unit time and Kamal's speed be 5x5x m/unit time, where xx is a constant.


Time taken by Meena to finish the race:

Time=DistanceSpeed\text{Time} = \dfrac{\text{Distance}}{\text{Speed}}

Time=3004x\text{Time} = \dfrac{300}{4x}

Time=75x\text{Time} = \dfrac{75}{x} units


When Meena finishes, Kamal has been running for the same time of 75x\dfrac{75}{x} units.

Distance covered by Kamal in this time:

Distance=Speed×Time\text{Distance} = \text{Speed} \times \text{Time}

Distance=5x×75x\text{Distance} = 5x \times \dfrac{75}{x}

Distance=375\text{Distance} = 375 metres


When Meena crosses the finish line at 500 metres, Kamal is at 375 metres.

Distance by which Meena wins:

500375=125500 - 375 = 125 metres

Therefore, Meena wins by 125 metres.

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