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The direction cosines of a line which makes equal angles with co-ordinate axes are:

Solution

✅ Correct Option: 1

Direction cosines are the cosines of the angles that a line makes with the x, y, and z axes. If a line makes angles α, β, and γ with the three axes, the direction cosines are:

l=cos⁡αl = \cos α (angle with x-axis)

m=cos⁡βm = \cos β (angle with y-axis)

n=cos⁡γn = \cos γ (angle with z-axis)

These satisfy the relation: l2+m2+n2=1l^2 + m^2 + n^2 = 1


The line makes equal angles with all three coordinate axes, so:

α=β=γ=θα = β = γ = θ

The direction cosines become:

l=cos⁡θl = \cos θ

m=cos⁡θm = \cos θ

n=cos⁡θn = \cos θ


Using l2+m2+n2=1l^2 + m^2 + n^2 = 1:

(cos⁡θ)2+(cos⁡θ)2+(cos⁡θ)2=1(\cos θ)^2 + (\cos θ)^2 + (\cos θ)^2 = 1

3cos⁡2θ=13 \cos^2 θ = 1

cos⁡2θ=13\cos^2 θ = \dfrac{1}{3}

cos⁡θ=±13\cos θ = ±\dfrac{1}{\sqrt{3}}


Since l=m=n=cos⁡θl = m = n = \cos θ:

Direction cosines =(±13,±13,±13)= \left(±\dfrac{1}{\sqrt{3}}, ±\dfrac{1}{\sqrt{3}}, ±\dfrac{1}{\sqrt{3}}\right)

The ±± sign accounts for the line pointing in two opposite directions.

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