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If three year moving averages for five data items given by 16, 18, 20, 10, 21 are xx, yy and zz respectively, then:

Solution

✅ Correct Option: 3

The data consists of 5 items: 16, 18, 20, 10, 21

A three year moving average takes 3 consecutive numbers and finds their average.

Since there are 5 data items, three moving averages can be calculated.


For the first three items:

x=16+18+203x = \dfrac{16 + 18 + 20}{3}

x=543x = \dfrac{54}{3}

x=18x = 18


For the second set of three consecutive items:

y=18+20+103y = \dfrac{18 + 20 + 10}{3}

y=483y = \dfrac{48}{3}

y=16y = 16


For the third set of three consecutive items:

z=20+10+213z = \dfrac{20 + 10 + 21}{3}

z=513z = \dfrac{51}{3}

z=17z = 17


Comparing the values:

x=18x = 18

y=16y = 16

z=17z = 17

Therefore: y<z<xy < z < x

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