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From the below-mentioned graph of shaded feasible region of a linear programming problem (LPP) with objective function

z=1.50x+1.00yz = 1.50x + 1.00y; the maximum value of zz will be:

Figure for CUET Mathematics 2025 22 May Shift 2 question 61 (Algebra)

Solution

✅ Correct Option: 2

In Linear Programming Problems, the maximum or minimum value of the objective function occurs at one of the corner points (vertices) of the feasible region.


From the shaded feasible region in the graph, the corner points are:

Point A: (0,0)(0, 0)

Point B: (35,0)(35, 0)

Point C: (25,15)(25, 15)

Point D: (0,25)(0, 25)


Substituting each corner point into the objective function z=1.50x+1.00yz = 1.50x + 1.00y:

At point A (0,0)(0, 0):

z=1.50(0)+1.00(0)z = 1.50(0) + 1.00(0)

z=0z = 0

At point B (35,0)(35, 0):

z=1.50(35)+1.00(0)z = 1.50(35) + 1.00(0)

z=52.5+0z = 52.5 + 0

z=52.5z = 52.5

At point C (25,15)(25, 15):

z=1.50(25)+1.00(15)z = 1.50(25) + 1.00(15)

z=37.5+15z = 37.5 + 15

z=52.5z = 52.5

At point D (0,25)(0, 25):

z=1.50(0)+1.00(25)z = 1.50(0) + 1.00(25)

z=0+25z = 0 + 25

z=25z = 25


Comparing all values:

zz at A =0= 0

zz at B =52.5= 52.5

zz at C =52.5= 52.5

zz at D =25= 25

Therefore, the maximum value of z=52.5z = 52.5

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