For a given data of 5 observation y = 311, x^2 = 10 and xy = 90. The equation of the trend line is : Option 1: y_t = 62.2 + 9x Option 2: y_t = 9 + 62.2x Option 3: y_t = 31.1 + 18x Option 4: y_t = 18 + 31.1x

Answer: y_t = 62.2 + 9x. Solution: Using coded x with x = 0: a = ( y)/n = 311/5 = 62.2. b = ( xy)/( x^2) = 90/10 = 9. Trend line: y_t = a + bx = 62.2 + 9x.

Applied Mathematics

Time Based Data

Medium

For a given data of 5 observation $\sum y = 311$ , $\sum x^2 = 10$ and $\sum xy = 90$ . The equation of the trend line is :

$y_t = 62.2 + 9x$

$y_t = 9 + 62.2x$

$y_t = 31.1 + 18x$

$y_t = 18 + 31.1x$

✅ Correct Option: 1

Using coded x with $\sum x = 0$ :

$a = \frac{\sum y}{n} = \frac{311}{5} = 62.2$ .

$b = \frac{\sum xy}{\sum x^2} = \frac{90}{10} = 9$ .

Trend line: $y_t = a + bx = 62.2 + 9x$ .

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For a given data of 5 observation ∑y=311\sum y = 311∑y=311, ∑x2=10\sum x^2 = 10∑x2=10 and ∑xy=90\sum xy = 90∑xy=90. The equation of the trend line is :

Solution

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CUET Mathematics Past Year Questions (Topic-Wise)

For a given data of 5 observation $\sum y = 311$ , $\sum x^2 = 10$ and $\sum xy = 90$ . The equation of the trend line is :