CUET Mathematics - If y = _e(e^2/x^2) for x ≠ 0, then d^2y/dx^2 equals | PYQs + Solutions

CUET Mathematics 2025 22 May Shift 2

Calculus

Medium

core

$-\frac{1}{x}$

$-\frac{1}{x^2}$

$\frac{2}{x^2}$

$-\frac{2}{x^2}$

✅ Correct Option: 3

Related questions:

22 May Shift 2

If the function

$f(x) = \begin{cases} ax + 2, & x \leq 1 \\ x^2 + 3x + b, & x > 1 \end{cases}$

is differentiable at $x = 1$ , then the value of $(2a + b)$ is

21 May Shift 2

$f(x) = \begin{cases} mx + 1,\ x \geq \pi/2 \\sin x + n, x \leq \pi/2, & \end{cases}$

is continuous at $x = \pi/2$ , where $m \in \mathbb{Z}$ (set of integers), then $\sin 2n =$

3 June Shift 2

Match List-I with List-II

List-I	List-II
(A) $\int \dfrac{dx}{x^2 - 16}$	(I) $\dfrac{1}{8} \log \left\| \dfrac{4 + x}{4 - x} \right\| + c$ , Where C is an arbitrary constant,
(B) $\int \dfrac{dx}{x^2 + 16}$	(II) $\log \left\| x + \sqrt{x^2 - 16} \right\| + c$ , Where C is an arbitrary constant,
(C) $\int \dfrac{dx}{16 - x^2}$	(III) $\dfrac{1}{8} \log \left\| \dfrac{x - 4}{x + 4} \right\| + c$ , Where C is an arbitrary constant,
(D) $\int \dfrac{dx}{\sqrt{x^2 - 16}}$	(IV) $\dfrac{1}{4} \tan^{-1} \left( \dfrac{x}{4} \right) + c$ , Where C is an arbitrary constant,

Choose the correct answer from the options given below:

CUET Mathematics 2025 22 May Shift 2 PYQs