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Ajesh has set up a sinking fund in order to have ₹ 10,00,000 after 10 years for his son's education. The amount should be set aside at the end of every 6 months into an account paying 5% per annum compounded half yearly is: [given (1.025)20=1.6386(1.025)^{20} = 1.6386]

Solution

✅ Correct Option: 3

Ajesh wants to save ₹ 10,00,000 for his son's education after 10 years by depositing equal amounts every 6 months into an account with 5% per annum interest compounded half-yearly.

Given information:

  • Target Amount (Future Value) = ₹ 10,00,000
  • Time Period = 10 years
  • Deposits made every 6 months
  • Interest Rate = 5% per annum compounded half-yearly
  • (1.025)20=1.6386(1.025)^{20} = 1.6386

Converting to half-yearly terms:

Number of deposits: n=10×2=20n = 10 \times 2 = 20

Interest rate per 6 months: i=5%2=2.5%=0.025i = \frac{5\%}{2} = 2.5\% = 0.025


The sinking fund formula relates the future value to regular deposits:

Future Value=P×(1+i)n−1i\text{Future Value} = P \times \frac{(1+i)^n - 1}{i}

where PP is the amount to deposit every 6 months.


Substituting the values:

10,00,000=P×(1.025)20−10.02510,00,000 = P \times \frac{(1.025)^{20} - 1}{0.025}

10,00,000=P×1.6386−10.02510,00,000 = P \times \frac{1.6386 - 1}{0.025}

10,00,000=P×0.63860.02510,00,000 = P \times \frac{0.6386}{0.025}


Simplifying:

0.63860.025=638.625=25.544\frac{0.6386}{0.025} = \frac{638.6}{25} = 25.544

10,00,000=P×25.54410,00,000 = P \times 25.544

P=10,00,00025.544P = \frac{10,00,000}{25.544}

P=39,148.1P = 39,148.1


Therefore, Ajesh needs to deposit ₹ 39,148.1 every 6 months.

This matches Option 3: ₹ 3,9,148.1 (in Indian numbering format).

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