Skip to main contentSkip to solution

A 95% confidence interval for a population mean was reported to be 152 to 160. If sample standard deviation σ=15\sigma=15, then sample size used in this study is (Given Z0.025=1.96Z_{0.025}=1.96)

Solution

✅ Correct Option: 4

Given information:

  • Confidence interval: 152 to 160
  • σ=15\sigma = 15
  • Z0.025=1.96Z_{0.025} = 1.96 (Z-value for 95% confidence)
  • Find: Sample size (n)(n)

The sample mean is at the center of the confidence interval.

Sample mean (xˉ)=152+1602(\bar{x}) = \dfrac{152 + 160}{2}

xˉ=3122\bar{x} = \dfrac{312}{2}

xˉ=156\bar{x} = 156


The margin of error is the distance from the mean to either endpoint of the interval.

Margin of Error (E)=160−156(E) = 160 - 156

E=4E = 4


The margin of error formula for a confidence interval is:

E=Z×σnE = Z \times \dfrac{\sigma}{\sqrt{n}}

Substituting the known values:

4=1.96×15n4 = 1.96 \times \dfrac{15}{\sqrt{n}}

4=29.4n4 = \dfrac{29.4}{\sqrt{n}}

4n=29.44\sqrt{n} = 29.4

n=29.44\sqrt{n} = \dfrac{29.4}{4}

n=7.35\sqrt{n} = 7.35


n=(7.35)2n = (7.35)^2

n=54.0225n = 54.0225

n≈54n \approx 54


Therefore, the sample size used in this study is 54.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question