Skip to main contentSkip to solution

The value of cot⁡(cos⁡−1725)\cot\left(\cos^{-1}\frac{7}{25}\right) is

Solution

✅ Correct Option: 4

Let θ=cos⁡−1725\theta = \cos^{-1}\frac{7}{25}

Then cos⁡θ=725\cos\theta = \frac{7}{25}


Consider a right triangle where:

Adjacent side =7= 7

Hypotenuse =25= 25


Using the Pythagorean theorem to find the opposite side:

(Opposite)2+72=252(Opposite)^2 + 7^2 = 25^2

(Opposite)2+49=625(Opposite)^2 + 49 = 625

(Opposite)2=576(Opposite)^2 = 576

Opposite=24Opposite = 24


The cotangent is given by:

cot⁡θ=AdjacentOpposite\cot\theta = \frac{Adjacent}{Opposite}

cot⁡θ=724\cot\theta = \frac{7}{24}

Therefore, cot⁡(cos⁡−1725)=724\cot\left(\cos^{-1}\frac{7}{25}\right) = \frac{7}{24}

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question