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The following data is available for two independent sample:

SAMPLE-1SAMPLE-2
sample size810
sample mean191199
sample standard deviation1012

Then the value of t-statistic is :

Solution

✅ Correct Option: 2

Pooled variance sp2=[(n1−1)s12+(n2−1)s22]/(n1+n2−2)=[7(100)+9(144)]/16=1996/16≈124.75s_p^2 = [(n_1-1)s_1^2 + (n_2-1)s_2^2]/(n_1+n_2-2) = [7(100) + 9(144)]/16 = 1996/16 \approx 124.75, so sp≈11.17s_p \approx 11.17. Standard error =sp1/n1+1/n2=11.170.225≈5.30= s_p\sqrt{1/n_1 + 1/n_2} = 11.17 \sqrt{0.225} \approx 5.30. Then t=(191−199)/5.30≈−1.51t = (191 - 199)/5.30 \approx -1.51, closest to −1.54-1.54.

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