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The value of sin⁡[π2−sin⁡−1(−32)]\sin\left[\frac{\pi}{2} - \sin^{-1}\left(-\frac{\sqrt{3}}{2}\right)\right] is :

Solution

✅ Correct Option: 1

sin⁡−1(−32)=−π3\sin^{-1}(-\frac{\sqrt{3}}{2}) = -\frac{\pi}{3}. So expression =sin⁡(π2+π3)=cos⁡(−π3)=cos⁡π3=12= \sin(\frac{\pi}{2}+\frac{\pi}{3}) = \cos(-\frac{\pi}{3}) = \cos\frac{\pi}{3} = \frac{1}{2}.

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