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If P is matrix of order m×nm \times n and Q is a matrix such that PQ' and Q'P are both computable, then the order of matrix Q is

Solution

✅ Correct Option: 1

Let Q be of order p×qp \times q, so QTQ^T is q×pq \times p. For PQTPQ^T computable: columns of P = rows of QTQ^T, so n=qn = q. For QTPQ^T P computable: columns of QTQ^T = rows of P, so p=mp = m. Hence Q is m×nm \times n.

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