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The area of the region {(x,y):y≥x2 and y≤∣x∣}\{(x, y) : y \geq x^2 \text{ and } y \leq |x|\} is

Solution

✅ Correct Option: 4

Region between y=x2y = x^2 (below) and y=∣x∣y = |x| (above) for −1≤x≤1-1 \le x \le 1. By symmetry: area =2∫01(x−x2) dx=2[x2/2−x3/3]01=2(1/2−1/3)=2/6=1/3= 2\int_0^1 (x - x^2)\,dx = 2[x^2/2 - x^3/3]_0^1 = 2(1/2 - 1/3) = 2/6 = 1/3.

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