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If y=sin⁡−1(1−x21+x2)y = \sin^{-1}\left(\frac{1-x^2}{1+x^2}\right) then dydx=\frac{dy}{dx} =

Solution

✅ Correct Option: 1

Let x=tan⁡θx = \tan\theta. Then (1−x2)/(1+x2)=cos⁡2θ(1 - x^2)/(1 + x^2) = \cos 2\theta. So y=sin⁡−1(cos⁡2θ)=π/2−2θ=π/2−2tan⁡−1xy = \sin^{-1}(\cos 2\theta) = \pi/2 - 2\theta = \pi/2 - 2\tan^{-1}x. Differentiating: dy/dx=−2/(1+x2)dy/dx = -2/(1 + x^2).

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