If A' = bmatrix -2 & 3 \\ 1 & 2 bmatrix and B = bmatrix -1 & 0 \\ 2 & 3 bmatrix then (3A + 2B)' is : Option 1: bmatrix -2 & 5 \\ 1 & 10 bmatrix Option 2: bmatrix 8 & 13 \\ -2 & 12 bmatrix Option 3: bmatrix -8 & 13 \\ 3 & 12 bmatrix Option 4: bmatrix 7 & 10 \\ -3 & 12 bmatrix

Answer: bmatrix -8 & 13 \\ 3 & 12 bmatrix. Solution: A = (A')' = bmatrix -2 & 1 \\ 3 & 2 bmatrix. Then 3A = bmatrix -6 & 3 \\ 9 & 6 bmatrix and 2B = bmatrix -2 & 0 \\ 4 & 6 bmatrix. So 3A + 2B = bmatrix -8 & 3 \\ 13 & 12 bmatrix. Transpose: bmatrix -8 & 13 \\ 3 & 12 bmatrix.

Applied Mathematics

Algebra

Medium

applied

If $A' = \begin{bmatrix} -2 & 3 \\ 1 & 2 \end{bmatrix}$ and $B = \begin{bmatrix} -1 & 0 \\ 2 & 3 \end{bmatrix}$

then $(3A + 2B)'$ is :

$\begin{bmatrix} -2 & 5 \\ 1 & 10 \end{bmatrix}$

$\begin{bmatrix} 8 & 13 \\ -2 & 12 \end{bmatrix}$

$\begin{bmatrix} -8 & 13 \\ 3 & 12 \end{bmatrix}$

$\begin{bmatrix} 7 & 10 \\ -3 & 12 \end{bmatrix}$

✅ Correct Option: 3

$A = (A')' = \begin{bmatrix} -2 & 1 \\ 3 & 2 \end{bmatrix}$ . Then $3A = \begin{bmatrix} -6 & 3 \\ 9 & 6 \end{bmatrix}$ and $2B = \begin{bmatrix} -2 & 0 \\ 4 & 6 \end{bmatrix}$ . So $3A + 2B = \begin{bmatrix} -8 & 3 \\ 13 & 12 \end{bmatrix}$ . Transpose: $\begin{bmatrix} -8 & 13 \\ 3 & 12 \end{bmatrix}$ .

2023: 30 May Shift 3

$5^{100} (\mod 9) =$

2023: 22 May Shift 3

If A is square matrix of order 3 with $|A| = 3$ , then $|4 \text{ adj} A|$ is equal to :

2026: 14 May Shift 2

If $A=\begin{bmatrix}0 & 1\\0 & 0\end{bmatrix}$ , then $A^{1999}$ is equal to

2022: 25 May Shift 1

Match List I with List II

LIST I	LIST II
A. The solution of $3x + 7 > 12$ is	I. $[-1, \infty)$
B. The solution of $\frac{3x+5}{2} \geq 1$ is	II. $\left[\frac{17}{8}, \infty\right)$
C. The solution of $2x + 5 < 7x + 9$ is	III. $\left(\frac{5}{3}, \infty\right)$
D. The solution of $6x - 5 \geq -2x + 12$ is	IV. $\left(-\frac{4}{5}, \infty\right)$

Choose the correct answer from the options given below:

2023: 7 June Shift 1

A die is thrown. If A is the event 'the number appearing is a multiple of 3 and B is the event 'the number appearing is even', then A and B are

2023: 11 Aug Shift 1

Solution for the inequality $|3x - 7| \leq 2$ is :

If A′=[−2312]A' = \begin{bmatrix} -2 & 3 \\ 1 & 2 \end{bmatrix}A′=[−21​32​] and B=[−1023]B = \begin{bmatrix} -1 & 0 \\ 2 & 3 \end{bmatrix}B=[−12​03​] then (3A+2B)′(3A + 2B)'(3A+2B)′ is :

Solution

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CUET Mathematics Past Year Questions (Topic-Wise)

If $A' = \begin{bmatrix} -2 & 3 \\ 1 & 2 \end{bmatrix}$ and $B = \begin{bmatrix} -1 & 0 \\ 2 & 3 \end{bmatrix}$

then $(3A + 2B)'$ is :