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The value of integral ∫4x2+9 dx\int \sqrt{4x^2 + 9}\, dx is

Solution

✅ Correct Option: 1

Use the standard formula ∫a2x2+b2 dx=(x/2)a2x2+b2+(b2/(2a))log⁡∣ax+a2x2+b2∣+C\int\sqrt{a^2 x^2 + b^2}\,dx = (x/2)\sqrt{a^2x^2+b^2} + (b^2/(2a))\log|ax + \sqrt{a^2x^2+b^2}| + C. With a=2,b2=9a=2, b^2=9, the result is (x/2)4x2+9+(9/4)log⁡∣2x+4x2+9∣+C(x/2)\sqrt{4x^2+9} + (9/4)\log|2x + \sqrt{4x^2+9}| + C. Option 1 most closely matches this structure.

Note: The log coefficient in option 1 is 9/29/2, while the textbook formula gives 9/49/4; we have picked option 1 as the closest intended answer.

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