The value of integral sqrt(4x^2 + 9) dx is Option 1: x/2sqrt(4x^2 + 9) + 9/2|2x + sqrt(4x^2 + 9)| + C Option 2: x/2sqrt(4x^2 + 9) + 3/2|2x + sqrt(4x^2 + 9)| + C Option 3: 2xsqrt(4x^2 + 9) + 9/2|2x + sqrt(4x^2 + 9)| + C Option 4: xsqrt(4x^2 + 9) + 9/4|2x + sqrt(4x^2 + 9)| + C

The answer is 'x/2sqrt(4x^2 + 9) + 9/2|2x + sqrt(4x^2 + 9)| + C'. View full solution:

CUET Mathematics - The value of integral sqrt(4x^2 + 9) dx is | PYQs + Solutions

CUET Mathematics 2023 23 May Shift 3

Calculus

Medium

$\frac{x}{2}\sqrt{4x^2 + 9} + \frac{9}{2}\log|2x + \sqrt{4x^2 + 9}| + C$

$\frac{x}{2}\sqrt{4x^2 + 9} + \frac{3}{2}\log|2x + \sqrt{4x^2 + 9}| + C$

$2x\sqrt{4x^2 + 9} + \frac{9}{2}\log|2x + \sqrt{4x^2 + 9}| + C$

$x\sqrt{4x^2 + 9} + \frac{9}{4}\log|2x + \sqrt{4x^2 + 9}| + C$

✅ Correct Option: 1

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