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If y=log⁡xx2y = \frac{\log x}{x^2}, then d2ydx2\frac{d^2y}{dx^2} is equal to

Solution

✅ Correct Option: 4

y=(log⁡x)/x2y = (\log x)/x^2. Quotient rule: y′=(1−2log⁡x)/x3y' = (1 - 2\log x)/x^3. Differentiating again: y′′=[x3(−2/x)−(1−2log⁡x)(3x2)]/x6=[−2x2−3x2+6x2log⁡x]/x6=(6log⁡x−5)/x4y'' = [x^3(-2/x) - (1 - 2\log x)(3x^2)]/x^6 = [-2x^2 - 3x^2 + 6x^2 \log x]/x^6 = (6\log x - 5)/x^4.

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