The value of (sqrt(x) + 1sqrt(x))^2 dx is: Option 1: x^2/2 + |x| + C, (where C is constant of integration) Option 2: x^2/2 + |x| + 2x + C, (where C is constant of integration) Option 3: 3/2(sqrt(x) + 1sqrt(x)) + C, (where C is constant of integration) Option 4: 2/3 x^3/2 + 2sqrt(x) + C, (where C is constant of integration)

The answer is 'x^2/2 + |x| + 2x + C, (where C is constant of integration)'. View full solution:

CUET Mathematics - The value of (sqrt(x) + 1sqrt(x))^2 dx is: | PYQs + Solutions

CUET Mathematics 2023 23 May Shift 3

Calculus

Easy

$\frac{x^2}{2} + \log|x| + C$ , (where C is constant of integration)

$\frac{x^2}{2} + \log|x| + 2x + C$ , (where C is constant of integration)

$\frac{3}{2}\left(\sqrt{x} + \frac{1}{\sqrt{x}}\right) + C$ , (where C is constant of integration)

$\frac{2}{3} x^{\frac{3}{2}} + 2\sqrt{x} + C$ , (where C is constant of integration)

✅ Correct Option: 2