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If 5x+y≤1005x + y \leq 100, x+y≤60x + y \leq 60, x≥0x \geq 0, y≥0y \geq 0. Then one of the corner points of the feasible region is :

Solution

✅ Correct Option: 3

Solve 5x+y=1005x + y = 100 and x+y=60x + y = 60 together: subtracting gives 4x=404x = 40, so x=10x = 10, y=50y = 50. Other corners are (0,0)(0,0), (20,0)(20,0), (0,60)(0,60). Among the listed options, (10,50)(10, 50) is a corner of the feasible region.

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