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If a⃗=5i^−j^−3k^\vec{a} = 5\hat{i} - \hat{j} - 3\hat{k} & b⃗=i^−3j^+5k^\vec{b} = \hat{i} - 3\hat{j} + 5\hat{k} the angle between a⃗+b⃗\vec{a} + \vec{b} and a⃗−b⃗\vec{a} - \vec{b} is :

Solution

✅ Correct Option: 2

∣a⃗∣2=25+1+9=35|\vec{a}|^2 = 25 + 1 + 9 = 35 and ∣b⃗∣2=1+9+25=35|\vec{b}|^2 = 1 + 9 + 25 = 35. Since the magnitudes are equal, (a⃗+b⃗)⋅(a⃗−b⃗)=∣a⃗∣2−∣b⃗∣2=0(\vec{a}+\vec{b}) \cdot (\vec{a}-\vec{b}) = |\vec{a}|^2 - |\vec{b}|^2 = 0. Hence the angle between them is 90 degrees.

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