Assertion [A]: Sum of the first hundred even natural numbers divisible by 5 is 45050. Reason (R): Sum of the first n-terms of an Arithmetic Progression is given by $S = (n/2) *(a + l)$ where a=first term, l=last term. Choose the correct answer from the options given below.
✅ Correct Option: 4
1) First, let's verify if [A] is true: - First hundred even numbers divisible by 5: 10, 20, 30,..., 1000 - This forms an AP with: * First term $a = 10$ * Common difference $d = 10$ * Number of terms $n = 100$ * Last term $l = 10 + (100-1)10 = 1000$ 2) Using formula given in [R]: $S = \frac{n}{2}(a + l)$ = $\frac{100}{2}(10 + 1000)$ = $50 × 1010$ = $50500$ 3) Therefore, [A] is false as it states sum is 45050. 4) Let's verify if [R] is true: - The formula given $S = \frac{n}{2}(a + l)$ is indeed correct for arithmetic progression - This is a standard formula for sum of AP - Therefore [R] is true
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