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The radii of two cones are in the ratio 2:3 and their volumes are in the ratio 1:3. Then the ratio of their heights is:

Solution

✅ Correct Option: 3
  1. Let's use the formula for volume of a cone:

V=13πr2hV = \frac{1}{3}πr^2h, where rr is radius and hh is height

  1. Given:
  • Ratio of radii (r1:r2)=2:3(r_1:r_2) = 2:3
    • Ratio of volumes (V1:V2)=1:3(V_1:V_2) = 1:3
  1. Let's express volume ratio using formula:

V1V2=13πr12h113πr22h2=r12h1r22h2=13\frac{V_1}{V_2} = \frac{\frac{1}{3}πr_1^2h_1}{\frac{1}{3}πr_2^2h_2} = \frac{r_1^2h_1}{r_2^2h_2} = \frac{1}{3}

  1. Now substitute radius ratio:

If r1r2=23\frac{r_1}{r_2} = \frac{2}{3}, then r12r22=49\frac{r_1^2}{r_2^2} = \frac{4}{9}

  1. Put this in volume ratio equation:

49×h1h2=13\frac{4}{9} × \frac{h_1}{h_2} = \frac{1}{3}

  1. Solve for height ratio:

h1h2=13×94=34\frac{h_1}{h_2} = \frac{1}{3} × \frac{9}{4} = \frac{3}{4}

Therefore, the ratio of heights (h1:h2)=3:4(h_1:h_2) = 3:4

The answer is 3:43:4.

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