JIPMAT Modern Math > Probability PYQs

A speaks truth in 75% cases and B in 80% of the cases. In what percentage of cases are they likely to contradict each other, in narrating the same incident?

Four persons are chosen at random from a group of 3 men, 2 women and 4 children. The chance that exactly 2 of them are children is:

A speaks the truth in $75 \%$ cases and $B$ in $80 \%$ of the cases. In what percentage of cases are they likely to contradict each other in narrating the same incident?

Let A and B be two events such that P(A)=0.25, P(B)=0.50 and P(A ∩ B)=0.14. The probability that neither A nor B occurs is:

<p>Given below are two statements in the context of throwing two different dice together:</p><p>Statement (I): The probability that the two numbers obtained have an even sum is 0.50.</p><p>Statement (II): The probability that the two numbers obtained have an even product is 0.75.</p><p>In light of the above statements, choose the most appropriate answer from the options given below.</p>

<p>The probabilities that A, B, and D can solve a problem independently are 1/3, 1/3, and 1/4 respectively. The probability that only two of them are able to solve the problem is:</p>

Given below are two statement based on the following If $A$ and $B$ are independent events such that $P(A)=p, P(B)=2 p$ and $P$ (exactly one of $A, B)=\frac{5}{9}$ Statement I: $\mathrm{p}=\frac{1}{3}$ Statement II: $\mathrm{p}=\frac{5}{12}$ In the light of the above statements, choose the correct answer form the question given below