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Given below are two statements in the context of throwing two different dice together:

Statement (I): The probability that the two numbers obtained have an even sum is 0.50.

Statement (II): The probability that the two numbers obtained have an even product is 0.75.

In light of the above statements, choose the most appropriate answer from the options given below.

Solution

✅ Correct Option: 1
  1. Statement (I): Probability of even sum = 0.500.50

Let's verify:

  • Possible sums: 2,3,4,5,6,7,8,9,10,11,122,3,4,5,6,7,8,9,10,11,12
  • Even sums: 2,4,6,8,10,122,4,6,8,10,12
  • Let's count favorable outcomes:
    • Sum 22: (1,1)(1,1)
    • Sum 44: (1,3),(2,2),(3,1)(1,3),(2,2),(3,1)
    • Sum 66: (1,5),(2,4),(3,3),(4,2),(5,1)(1,5),(2,4),(3,3),(4,2),(5,1)
    • Sum 88: (2,6),(3,5),(4,4),(5,3),(6,2)(2,6),(3,5),(4,4),(5,3),(6,2)
    • Sum 1010: (4,6),(5,5),(6,4)(4,6),(5,5),(6,4)
    • Sum 1212: (6,6)(6,6)
  • Total favorable outcomes = 1818
  • Total possible outcomes = 3636 (6×66×6)
  • Probability = 1836=0.50\frac{18}{36} = 0.50

Therefore Statement (I) is TRUE

  1. Statement (II): Probability of even product = 0.750.75

Let's verify:

  • A product is even if at least one number is even
  • On a die, even numbers are 2,4,62,4,6 (33 numbers)
  • Odd numbers are 1,3,51,3,5 (33 numbers)
  • For odd product, both numbers must be odd
  • Probability of odd product = 36×36=14=0.25\frac{3}{6}×\frac{3}{6} = \frac{1}{4} = 0.25
  • Therefore probability of even product = 1−0.25=0.751 - 0.25 = 0.75

Therefore Statement (II) is TRUE

Hence, both statements are true.

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