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Arrange the following in descending order:

A. $\sqrt{401}-\sqrt{399}$

B. $\sqrt{301}-\sqrt{299}$

C. $\sqrt{101}-\sqrt{99}$

D. $\sqrt{201}-\sqrt{199}$

Choose the correct answer from the options given below:

The value of $3+\frac{1}{\sqrt3}+\frac{1}{3+\sqrt3}+\frac{1}{\sqrt3-3}$ is

$\sqrt{2+\sqrt{3}} \times \sqrt{2+\sqrt{2+\sqrt{3}}} \times \sqrt{2+\sqrt{2+\sqrt{2+\sqrt{3}}}} \times \sqrt{2-\sqrt{2+\sqrt{2+\sqrt{3}}}}$ is equal to

Simplify : $\dfrac{\sqrt[4]{0.0625}+\sqrt[3]{0.008}+\sqrt{0.09}-1}{\sqrt[3]{62 \cdot 5 \times \sqrt[5]{32}}}$

$\sqrt{3+\sqrt{5}}=$

$\frac{\sqrt{5}+\sqrt{3}}{\sqrt{8-2 \sqrt{15}}}+\frac{\sqrt{11+2 \sqrt{30}}}{\sqrt{6}-\sqrt{5}}$

If $2^{x} = 3^{y} = 6^{-z}$, then $(\frac{1}{x} + \frac{1}{y} + \frac{1}{z})$ is equal to