Q1:
JIPMAT 2025
Algebra > Indices
Hard
$\sqrt{2+\sqrt{3}} \times \sqrt{2+\sqrt{2+\sqrt{3}}} \times \sqrt{2+\sqrt{2+\sqrt{2+\sqrt{3}}}} \times \sqrt{2-\sqrt{2+\sqrt{2+\sqrt{3}}}}$ is equal to
Correct Answer
Option 1
Correct Answer
JIPMAT Algebra > Indices PYQs
No login required. No pop-ups. We have all previous-year questions with solutions for free!
Q2:
JIPMAT 2024
Algebra > Indices
Easy
<style> table { border-collapse: collapse; margin: 10px 0; } th, td { border: 1px solid #ccc; text-align: left; padding: 8px; } th { background-color: #f2f2f2; color: #333; } tr:nth-child(even) { background-color: #f9f9f9; } </style>Match List I with List II <br> <table> <tr><th></th><th>List-I (Expression)</th><th></th><th>List-II (Absolute Value)</th> </tr> <tr><td>(A)</td><td>$$\sqrt{15 \times 163 \div 5-89}$$</td><td>(I)</td><td>105</td> </tr> <tr><td>(B)</td><td>$$\sqrt{15^{2}+11 \times 3^{2}}$$</td><td>(II)</td><td>20</td> </tr> <tr><td>(C)</td><td>$$\sqrt{8^{2} \times 7 \times 5^{2}-175}$$</td><td>(III)</td><td>10</td> </tr> <tr><td>(D)</td><td>$$\sqrt{91+\sqrt{70+\sqrt{121}}}$$</td><td>(IV)</td><td>18</td> </tr></table>
Choose the correct answer from the options given below :
Correct Answer
Option 3
Correct Answer
Q3:
JIPMAT 2024
Algebra > Indices
Easy
Simplify : $\dfrac{\sqrt[4]{0.0625}+\sqrt[3]{0.008}+\sqrt{0.09}-1}{\sqrt[3]{62 \cdot 5 \times \sqrt[5]{32}}}$
Correct Answer
Option 3
Correct Answer
Q4:
JIPMAT 2023
Algebra > Indices
Medium
$\sqrt{3+\sqrt{5}}=$
Correct Answer
Option 2
Correct Answer
Q5:
JIPMAT 2022
Algebra > Indices
Hard
$\frac{\sqrt{5}+\sqrt{3}}{\sqrt{8-2 \sqrt{15}}}+\frac{\sqrt{11+2 \sqrt{30}}}{\sqrt{6}-\sqrt{5}}$
Correct Answer
Option 4
Correct Answer
Q6:
JIPMAT 2021
Algebra > Indices
Medium
If $2^{x} = 3^{y} = 6^{-z}$, then $(\frac{1}{x} + \frac{1}{y} + \frac{1}{z})$ is equal to
Correct Answer
Option 1
Correct Answer