JIPMAT - The expression 2x3 + ax2 + bx + 3, where a and b are constants, has a factor of x-1 and leaves a remainder of 15 when divided by x + 2. Then, (a, b) = | PYQs + Solutions

JIPMAT

Number System

Easy

(-3,8)

(3,-8)

(-3,-8)

(3, 8)

✅ Correct Option: 2

Related questions:

JIPMAT 2022

Given below are two statements:

Statement I : The sum of exponents of prime factors in the prime factorization of 392 is 5.

Statement II : The decimal representation $\frac{13}{2^3 \times 5}$ will terminate after 2 decimal places.

In the light of the above statements, choose the correct answer from the options given below:

JIPMAT 2025

After adding 5 to both numerator and denominator of the following fractions, arrange them in ascending order of the magnitude of change in their values.

A. $\frac{2}{3}$

B. $\frac{3}{4}$

C. $\frac{4}{5}$

D. $\frac{5}{6}$

JIPMAT 2023

Amicable numbers are a pair of distinct natural numbers (a, b) such that the sum of the proper divisors of a equals b and the sum of the proper divisors of b equals a. Given that (220, y) is a pair of amicable numbers, y equals:

JIPMAT (QA) PYQs

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