JIPMATGeometry > Easy56\frac{5}{6}6565\frac{6}{5}562222518\frac{25}{18}1825✅ Correct Option: 4Related questions:JIPMAT 2022Given below are two statement: Statement I: If sin(θ)=513\sin (\theta)=\frac{5}{13}sin(θ)=135, then the value of tan(θ)=512\tan (\theta)=\frac{5}{12}tan(θ)=125 Statement II: if cot(θ)=125\cot (\theta)=\frac{12}{5}cot(θ)=512, then the value of sin(θ)=512\sin (\theta)=\frac{5}{12}sin(θ)=125 In the light of the above statements, choose the correct answer form the question below:JIPMAT 2022Which of the following trigonometric identities are true? sin2(41∘)+sin2(49∘)=1sin2(60∘)−2tan(45∘)−cos2(30∘)=−1sin2(θ)+11+tan2(θ)=1\begin{aligned} & \sin ^2\left(41^{\circ}\right)+\sin ^2\left(49^{\circ}\right)=1 \\ & \sin ^2\left(60^{\circ}\right)-2 \tan \left(45^{\circ}\right)-\cos ^2\left(30^{\circ}\right)=-1 \\ & \sin ^2(\theta)+\frac{1}{1+\tan ^2(\theta)}=1 \end{aligned}sin2(41∘)+sin2(49∘)=1sin2(60∘)−2tan(45∘)−cos2(30∘)=−1sin2(θ)+1+tan2(θ)1=1JIPMAT 2025If sinθ+cosθsinθ−cosθ=3\frac{\sin\theta + \cos\theta}{\sin\theta - \cos\theta} = 3sinθ−cosθsinθ+cosθ=3, then value of sin4θ−cos4θ\sin^4\theta - \cos^4\thetasin4θ−cos4θ is