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Given below are two statements:

Statement (I): (x2 + 3x + 1) = (x - 2)2 is not a quadratic equation.

Statement (II): The nature of roots of quadratic equations x2 + 2x√3 + 3 = 0 are real and equal.

In light of the above statements, choose the most appropriate answer from the options given below.

Solution

✅ Correct Option: 1

Statement (I): (x2+3x+1)=(x−2)2(x^2 + 3x + 1) = (x - 2)^2 is not a quadratic equation

  1. Let's expand (x−2)2(x - 2)^2:

= x2−4x+4x^2 - 4x + 4

  1. So the equation becomes:

x2+3x+1=x2−4x+4x^2 + 3x + 1 = x^2 - 4x + 4

  1. Rearranging:

x2+3x+1−(x2−4x+4)=0x^2 + 3x + 1 - (x^2 - 4x + 4) = 0

7x−3=07x - 3 = 0

x=37x = \frac{3}{7}

  1. This is a linear equation, not quadratic

Therefore Statement (I) is TRUE

Statement (II): The roots of x2+2x3+3=0x^2 + 2x\sqrt{3} + 3 = 0 are real and equal

  1. For quadratic equation ax2+bx+c=0ax^2 + bx + c = 0

Here, a=1a=1, b=23b=2\sqrt{3}, c=3c=3

  1. For real and equal roots:

Discriminant = b2−4ac=0b^2 - 4ac = 0

  1. Let's calculate:

= (23)2−4(1)(3)(2\sqrt{3})^2 - 4(1)(3)

= 12−1212 - 12

= 00

  1. Since discriminant = 0, roots are real and equal

Therefore Statement (II) is TRUE

Hence both statements are true.

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