Q1:

JIPMAT 2026

Divisibility Rules

Hard

2122+462+842+464+21302^{122}+4^{62}+8^{42}+4^{64}+2^{130} is divisible by which one of the following integers?

Answer options
Option 4
Correct Answer
Explanation for JIPMAT 2026 QA question 1

Q2:

JIPMAT 2026

Divisibility Rules

Hard

Find the maximum value of nn such that

61×42×26×81×64×49×47×51×63×16×6761 \times 42 \times 26 \times 81 \times 64 \times 49 \times 47 \times 51 \times 63 \times 16 \times 67 is perfectly divisible by 56n56^n

Answer options
Option 3
Correct Answer
Explanation for JIPMAT 2026 QA question 2

Q3:

JIPMAT 2025

Divisibility Rules

Medium

2122+462+842+464+21302^{122} + 4^{62} + 8^{42} + 4^{64} + 2^{130} is divisible by which one of the following integers?

Answer options
Option 4
Correct Answer
Explanation for JIPMAT 2025 QA question 3

Q4:

JIPMAT 2024

Divisibility Rules

Medium

If the seven digit number 94a29b694 a 29 b 6 is divisible by 72 , then what is the value of (2a+3b)(2 a+3 b) for a≠ba \neq b ?

Answer options
Option 2
Correct Answer
Explanation for JIPMAT 2024 QA question 4

Q5:

JIPMAT 2023

Divisibility Rules

Conceptual

If k2 - 1 is divisible by 8, then K is:

Answer options
Option 4
Correct Answer
Explanation for JIPMAT 2023 QA question 5

Q6:

JIPMAT 2023

Divisibility Rules

Medium

If the eight-digit number 5a32465b5a32465b is divisible by 8888, then 2a+5b=2a+ 5b =

Answer options
Option 1
Correct Answer
Explanation for JIPMAT 2023 QA question 6