Skip to main contentSkip to solution

Navin got 60% of the maximum marks in his college's exam for his batch but missed that year's 'Deans List' threshold by 60 marks. His batchmate Pravin scored 80% of the maximum, and this score was 40 marks more than the same threshold. What was that year's 'Deans List' threshold?

Solution

✅ Correct Option: 1

Let the maximum marks =M= M and the Dean's List threshold =T= T.

Navin scored 60% of max marks but fell short of the threshold by 60 marks:

0.6M=T−60...(1)0.6M = T - 60 \quad \text{...(1)}

Pravin scored 80% of max marks, which was 40 marks more than the threshold:

0.8M=T+40...(2)0.8M = T + 40 \quad \text{...(2)}


Subtracting Equation (1) from Equation (2):

0.8M−0.6M=(T+40)−(T−60)0.8M - 0.6M = (T + 40) - (T - 60)

0.2M=1000.2M = 100

M=500M = 500


Substituting M=500M = 500 in Equation (1):

0.6×500=T−600.6 \times 500 = T - 60

300=T−60300 = T - 60

T=360T = 360

The threshold is 360 marks, which does not match any of the given numerical options.


The answer is Option 1 — None of these.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question