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In the given figure, two concentric circles with centre O have radii 14 cms and 7 cms. If ∠AOB=30∘\angle AOB = 30^{\circ}, find the area of the shaded region.

Figure for BMSAT Kozhikode 2026 QA question 15 (Geometry)

Solution

✅ Correct Option: 1

The shaded region is the ring (area between the two circles) excluding the 30°30° sector between radii OA and OB.


Area of the ring =πR2−πr2= \pi R^2 - \pi r^2

=π(R2−r2)= \pi(R^2 - r^2)

=π(142−72)= \pi(14^2 - 7^2)

=π(196−49)= \pi(196 - 49)

=147π= 147\pi


The unshaded part is the 30°30° sector of the ring, so the shaded part spans 360°−30°=330°360° - 30° = 330° of the ring.

Shaded Area =330°360°×147π= \dfrac{330°}{360°} \times 147\pi

=1112×147π= \dfrac{11}{12} \times 147\pi


Using π=227\pi = \dfrac{22}{7}:

=1112×147×227= \dfrac{11}{12} \times 147 \times \dfrac{22}{7}

=1112×21×22= \dfrac{11}{12} \times 21 \times 22

=1112×462= \dfrac{11}{12} \times 462

=508212= \dfrac{5082}{12}

=423.5= 423.5 sq. cms

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