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In normal times, a vegetable exporter assumes that 20% of the produce sent in a container will perish by the end of the voyage to international markets, and he prices the sent vegetables at Rs 2L per ton to enjoy a 20% profit. Due to difficult shipping conditions now, he estimates that 50% of his produce inside the container will become unsellable, despite transport costs per container also increasing from Rs 2L to Rs 4L. If a container can store 10 tons of vegetables, what would be the new price he would ask (per ton) to retain his profit?

Solution

✅ Correct Option: 2

A container holds 1010 tons of vegetables.

In normal times, 20%20\% perishes, so sellable quantity =10×0.8=8= 10 \times 0.8 = 8 tons.

He sells at Rs 22L per ton, so:

Revenue =8×2=16= 8 \times 2 = 16L

Since this gives him a 20%20\% profit:

Total Cost =161.2=13.33= \dfrac{16}{1.2} = 13.33L

This total cost includes transport (Rs 22L) and the cost of goods:

Cost of goods =13.33−2=11.33= 13.33 - 2 = 11.33L

We separate these because transport cost changes in the new scenario, but the cost of goods stays the same.


In the new scenario:

  • 50%50\% perishes → sellable quantity =10×0.5=5= 10 \times 0.5 = 5 tons
  • Transport cost rises from Rs 22L to Rs 44L
  • Cost of goods remains Rs 11.3311.33L

New total cost =11.33+4=15.33= 11.33 + 4 = 15.33L


He still wants a 20%20\% profit, so:

Required revenue =15.33×1.2=18.4= 15.33 \times 1.2 = 18.4L

This revenue must come from just 55 sellable tons:

New price per ton =18.45=3.68= \dfrac{18.4}{5} = 3.68L


The new price he would ask is Rs 3.683.68L per ton.

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