BMSAT KozhikodeGeometry > Easy45∘45^{\circ}45∘30∘30^{\circ}30∘90∘90^{\circ}90∘60∘60^{\circ}60∘✅ Correct Option: 4Related questions:BMSAT Kozhikode 2025If a pole 6 m high casts a shadow 232\sqrt{3}23 m long on the ground, then the sun's elevation is2026If cosα+cosβ+cosγ=3\cos\alpha + \cos\beta + \cos\gamma = 3cosα+cosβ+cosγ=3, then cos3α+cos3β+cos3γ\cos^3\alpha + \cos^3\beta + \cos^3\gammacos3α+cos3β+cos3γ will be2026In △ABC\triangle ABC△ABC, ∠A=90∘\angle A = 90^{\circ}∠A=90∘, if tanC=3\tan C = \sqrt{3}tanC=3, then find the value of sinB+cosC−cos2B\sin B + \cos C - \cos^2 BsinB+cosC−cos2B