20:[["$","title","0",{"children":"BMSAT Kozhikode - The sides of a triangle are 2006 cm, 6002 cm and 'm' cm, where m is a positive integer. How many values of 'm' are possible? | PYQs + Solutions | AfterBoards"}],["$","meta","1",{"name":"description","content":"undefined By the Triang<= Inequality Theorem, the sum of any two sides of a triang<= must be strictly greater than the third side. The three sides are 2006, 6002, and m. This gives us three conditions: 2006 + 6002 > m m < 8008 2006 + m > 6002 m > 3996 6002 + m > 2006 m > -3996 (always true since m is positive)

Combining the useful conditions: 3996 < m < 8008 Since m is a positive inte>=r, m can take values from 3997 to 8007.

Total number of values = 8007 - 3997 + 1 = 4011"}],["$","link","2",{"rel":"manifest","href":"https://www.afterboards.in/manifest.json","crossOrigin":"$undefined"}],["$","meta","3",{"name":"keywords","content":"BMSAT Kozhikode,QA,Geometry,Triangles"}],["$","meta","4",{"name":"robots","content":"index, follow"}],["$","meta","5",{"name":"category","content":"education"}],["$","meta","6",{"name":"google-site-verification","content":"google"}],["$","meta","7",{"name":"mobile-web-app-capable","content":"yes"}],["$","meta","8",{"name":"apple-mobile-web-app-title","content":"AfterBoards"}],["$","meta","9",{"name":"apple-mobile-web-app-status-bar-style","content":"default"}],["$","meta","10",{"property":"og:title","content":"BMSAT Kozhikode - The sides of a triangle are 2006 cm, 6002 cm and 'm' cm, where m is a positive integer. How many values of 'm' are possible? | PYQs + Solutions"}],["$","meta","11",{"property":"og:description","content":"undefined By the Triang<= Inequality Theorem, the sum of any two sides of a triang<= must be strictly greater than the third side. The three sides are 2006, 6002, and m. This gives us three conditions: 2006 + 6002 > m m < 8008 2006 + m > 6002 m > 3996 6002 + m > 2006 m > -3996 (always true since m is positive)

Combining the useful conditions: 3996 < m < 8008 Since m is a positive inte>=r, m can take values from 3997 to 8007.

Total number of values = 8007 - 3997 + 1 = 4011"}],["$","meta","12",{"property":"og:url","content":"https://www.afterboards.in/past-year-questions/iimk-bmsat/2026/QA/10"}],["$","meta","13",{"property":"og:site_name","content":"AfterBoards | BMSAT Kozhikode Preparation"}],["$","meta","14",{"property":"og:image","content":"https://www.afterboards.in/pyp/AfterBoards%20CUET%20Past%20Year%20Papers%20with%20Solutions.webp"}],["$","meta","15",{"property":"og:type","content":"website"}],["$","meta","16",{"name":"twitter:card","content":"summary_large_image"}],["$","meta","17",{"name":"twitter:site","content":"afterboards.in"}],["$","meta","18",{"name":"twitter:title","content":"BMSAT Kozhikode - The sides of a triangle are 2006 cm, 6002 cm and 'm' cm, where m is a positive integer. How many values of 'm' are possible? | PYQs + Solutions"}],["$","meta","19",{"name":"twitter:description","content":"undefined By the Triang<= Inequality Theorem, the sum of any two sides of a triang<= must be strictly greater than the third side. The three sides are 2006, 6002, and m. This gives us three conditions: 2006 + 6002 > m m < 8008 2006 + m > 6002 m > 3996 6002 + m > 2006 m > -3996 (always true since m is positive)

Combining the useful conditions: 3996 < m < 8008 Since m is a positive inte>=r, m can take values from 3997 to 8007.

Total number of values = 8007 - 3997 + 1 = 4011"}],["$","meta","20",{"name":"twitter:image","content":"https://www.afterboards.in/pyp/AfterBoards%20CUET%20Past%20Year%20Papers%20with%20Solutions.webp"}],["$","link","21",{"rel":"shortcut icon","href":"https://www.afterboards.in/favicon.ico","type":"image/x-icon","sizes":"48x48"}],"$L2e","$L2f","$L30","$L31","$L32","$L33","$L34","$L35"]

BMSAT Kozhikode (QA) PYQs

Keyboard Shortcuts